有两种方法。简单的方法是使用 -run 标志并提供一个匹配要运行的测试名称的模式。

$ go test -run NameOfTest 。有关更多信息，请参见文档。

另一种方法是命名包含要运行的测试的特定文件：

  $ go test foo_test .go 
 

但有一个问题。如果

• foo.go是包foo


• foo_test.go是包foo_test，如果'foo_test.go'和'foo.go'是同一个软件包（一种常见的情况），那么这个软件包就是一个'foo'。那么你必须命名构建'foo_test'所需的所有其他文件。在这个例子中，它是：
  
  

  $ go test foo_test.go foo.go 
 

我建议使用名称模式。或者，在/可能的情况下，始终运行所有包装测试。

My package test cases are scattered across multiple files, if I run go test <package_name> it runs all test cases in the package.

It is unnecessary to run all of them though. Is there a way to specify a file for go test to run, so that it only runs test cases defined in the file?

There are two ways. The easy one is to use the -run flag and provide a pattern matching names of the tests you want to run.

ex: $ go test -run NameOfTest. See the docs for more info.

The other way is to name the specific file, containing the tests you want to run:

$ go test foo_test.go

But there's a catch. This works well if

• foo.go is package foo
• foo_test.go is package foo_test and imports 'foo'.

If 'foo_test.go' and 'foo.go' are the same package (a common case), then you must name all other files required to build 'foo_test'. In this example it would be:

$ go test foo_test.go foo.go

I'd recommend to use the name pattern. Or, where/when possible, always run all package tests.